Need help with making a graph for capacitor voltage!?

ok, the formula is given for 0v - 5v ----> 5(1-e^(-t/tou))... then, when the voltage gets to 5v, the circuit responce will now discharge with the equation ---> 5e^(-t/tou)... how do you make the graph (using the discharge function) so it will go with the flow of time... independent variable is time and dependent is voltage